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I can't figure this out to confirm, from definitions of solar-efficiency (examples there don't specify rated wattage):

Will two separate solar panels that are identical (including rated wattage), except differing only by solar-efficiency, produce the same power wattage output (in identical conditions, in a given equal time)?

Would the lower-efficiency panel produce less, or would it be identical because the manufacturer-rated wattage is identical to the other panel?

I can't figure out if efficiency is already taken into account before the manufacturer-rating of a panel's wattage, or if it should be taken into account when calculating real-world output. I know that real-world performance will never meet advertised (ideal-condition) wattage; but whatever the real-world performance is, I want to confirm if it will be identical (or not) between two identical panels that only differ by solar-efficiency.

In other words, which of the below is valid [maybe we should say, assuming "ideals", like Standard Test Condition 1 Kw/m^2 irradiance]?

The Answer is A

A) Real-world kW output = Wattage kW * Number of hours

B) Real-world kW output = Solar-efficiency * Wattage kW * Number of hours

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  • I think you are doing thing in the inverse way. What is the real-world kW of a lamp? In other words, do you think the mean power is something people care? -- In any case, maybe electronics SE may be more appropriate site to ask. IMHO cost-efficiency should already be in the "installed power". -- Note sometime efficiency is not about the output part (solar panel with regulators, etc.)? Commented Oct 4 at 8:07
  • OK thanks for trying to help. My Question was about solar-efficiency - that is different from the cost efficiency you mention (my Question did not mention cost efficiency). I plan to close this Question here, and re-ask on a different stack. Thanks for your Electronics SE suggestion.
    – cellepo
    Commented Oct 5 at 15:58
  • In any case: does it matter? Usually we care about the installed power of a panel (and costs per installed-W). So what efficiency would tell us? At first I would say about the size (more efficient a 100W panel, smaller should be), or how dense the silicon is placed (compared wiring), and I think nearly irrelevant: resistance inside wiring). For sure you get better efficiency if you use a worse glass, which will not withstand hail and snow and possibly rain). -- Note: on research side is good indicator, but we want the watt per panel (and size). Commented Oct 7 at 7:03
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    This answer (but closed as off-topic) may give some hints on where efficiency is included (or not): electronics.stackexchange.com/questions/726979/… Commented Oct 7 at 7:07

2 Answers 2

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No. They will not be exactly the same in how much power they produce, but you can expect them to be fairly close, within 2%-5% depending on temperature and intensity of light. There are simple tests you can perform to more accurately determine the output of each unit individually. Efficiency shouldn't even be part of this calculation even if it does have a small effect on changes in the output as they degrade over time. Efficiency is only taken into account when you are trying to determine how much area different panels require.

Additionally, both of your formulas are incorrect and will cause you much confusion if you try to use them. The Kilowatt hours should be Kilowatts times hours, and not the other way around as you have them.

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  • Thanks! And formulas fixed. Yeah within 2-5% difference is definitely tolerable for the estimating I am doing.
    – cellepo
    Commented Oct 13 at 1:10
  • This was also helpful: "Efficiency is only taken into account when you are trying to determine how much area different panels require."
    – cellepo
    Commented Oct 15 at 17:42
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    @cellepo Awesome, but the formula is still wrong. Kilowatt Hours (kWh) is how much power is produced per hour, so: kWh = kw times hours. Commented Oct 16 at 6:04
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Solar panels that have been manufactured differently can very well differ in the I-V curve.

You can find the I-V model from Wikipedia: https://en.wikipedia.org/wiki/Theory_of_solar_cells#Equivalent_circuit_of_a_solar_cell

Specifically, the reverse saturation current and diode ideality factor could differ.

So a different solar panel, even if of the same wattage and same number of cells in series, can have slightly different characteristics.

If you have an MPPT charge controller or inverter, then it is supposed to find the maximum power point. A 100 W panel, no matter what the efficiency is, should produce 100 W at the maximum power point given standard illumination conditions. A lower efficiency panel just has more surface area to do that.

However, this is only at standard illumination conditions and only with MPPT. If the illumination conditions differ from standard, such as during cloudy weather or solar panel not directly facing the sun, or sun near the horizon with lots of air mass inbetween sun and panels, there can be a percent or two difference in the output of two panels of the same power.

Also without MPPT with a PWM charge controller, you're at the mercy of what the power output is at the point of the I-V curve where your battery accepts charge. Then two nominally 100 W panels can have even greater differences in their output than a percent or two.

The efficiency has already been taken into account in the output. So a 100 W panel with 16% efficiency is a 100 W panel, not a 16 W panel, and a 100 W panel with 20% efficiency is a 100 W panel, not a 20 W panel. But different solar cells can have a percent or two difference in the output if the illumination conditions are non-standard.

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    "The efficiency has already been taken into account in the output." That answered my Question, thanks! And I acknowledge they may be close, but not exactly the same (because of illumination as you describe, for example).
    – cellepo
    Commented Oct 15 at 17:39

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