# What's needed to set up a personal solar power system?

I'd like to set up a solar power system to power a small house, say 20 kWh per day, 600 kWh per month.

What equipment do I need to make it happen? Production and storage are both important. I'm looking for a full shopping list and ways of estimating the sizing that I'll need.

• how much power you consume per day? Commented May 30, 2013 at 18:02
• It's on the low side - probably 20 KwH per day. 600 a month. Commented May 30, 2013 at 18:05
• Where in the world are you? And are you connected to the electricity grid? Do you want self-sufficiency on average over the year (i.e. grid exports are at least as big as grid imports), or every day of the year? Commented May 30, 2013 at 19:35
• Located in Israel, and looking to detach from the grid completely. Commented Jun 1, 2013 at 17:53
• Also useful - euanmearns.com/… Commented Nov 5, 2015 at 7:50

For estimating the solar power system requirement it depends on mainly following factor

2. Sun light peak value.
4. How much energy can a Solar panel generate over a period of time?

there are many walls solar panel is available lets take one example

The power generation rating of a Solar panel is also given in Watts (eg STP010, 10W). To calculate the energy it can supply to the battery, multiply Watts by the hours exposed to sunshine, then multiply the result by 0.85 (this factor allows for natural system losses).

For the Solar 100W panel in 4 hours* of sunshine, `100 x 4 x 0.85 = 340WH`. This is the amount of energy the Solar panel can supply to the battery.

``````As your requirement is 600000 so per day is 20000
``````

So according to your requirement 20 kwh per day so you need `20000/340=59` panel

and for easy calculation i found one site Calculate Estimate of solar power system

Here is a list of the PV system basics:

`````` 1. Panels

2. Mounting equipment

3. DC-to-AC inverters

4. Tracking mounts

5. Disconnect switches

6. Wiring and fuse box connections

7. Utility power meters
``````

Storage device

As your electical power usually needs to be available when the sun is not shining, it usually neccessary to store electricity.
Now a days there are many types of batteries and generator are available which stores the electricity produced by solar panel. The normal storage is the Lead-Acid battery.

• 10 peak hours of sun in a month? That's incredibly low. Have you mistakenly compared daily production with monthly demand? But then, 10 peak hours of sun in a day would be way too high: somewhere in the range 3-6 is much more likely. Commented May 30, 2013 at 19:38
• The only issue with this setup (and it won't be an issue for everyone) is that it doesn't allow the solar panels to power the house if the grid connection fails due to safety concerns for maintenance workers. It is possible to use a setup similar to the wiring for an emergency generator, but that usually involves the addition of expensive batteries. Commented May 30, 2013 at 21:18
• @EnergyNumbers i just given the example let me modify it Commented May 31, 2013 at 5:20
• You're still comparing daily sun with monthly demand. And tracking mounts are by no means a systems basic: most PV systems don't have them, because they're simply not worth the additional maintenance. Commented May 31, 2013 at 7:52
• @EnergyNumbers thanks for finding fault , oh i got it i just misunderstand i modified it, is that ok now? Commented May 31, 2013 at 7:56

I'm answering only the estimating part of your question, the other answers cover the rest of the question satisfactorily.

I estimated your future system by your requirements in African PV GIS for Haifa (you can elaborate more for yourself).
You'll need at least PV grid of 7kWp. The area of the PV grid would be approx. 40 m2.
The optimized setup would be inclination=28°, orientation=-15° (15° from South towards East). The yearly approx. total energy production would be 11100 kWh with a daily average of 30.4 kWh. The critical month is December with only average 19.00 kWh per day.

This catch can be partly avoided by raising the PV inclination to let's say 45° (orientation=-15°). The total energy production would then be 4% lower, but average daily production in December would be 20.70 kWh (9% more).

To backup your system from batteries for 3 days would mean at least 60 kWh of storage capacity. It would mean at least 1500 Ah of 12 V 48 V batteries. Not to damage the batteries too quickly one usually doubles the storage capacity (3000 Ah of 48 V batteries).

There is an important remark on this:
To disconnect this relatively big energy demand (20 kWh a day) from grid will be rather expensive. You should try to optimize your energy consumption as mentioned in many answers on this site. If your consumption was a maximum estimate, the number would be lower.